13 in the
following way. Suppose it is required to find the discharge in
cubic feet per minute when the depth of water measured in the
middle of the notch is 4 in Using Santo Crimp's formula the
result will be
C\/H^3 = 4.69 \/4^3 = 4.69 x 8 = 37.52
cubic feet per foot in width of weir, but as the weir is only 6
in wide, we must divide this figure by 2, then
37.52/2 = 18.76 cubic feet, which is the discharge per minute.
+------+ +------+
| | FIG. 13 | |
| | | |
| | | |
| +------+ +------+ |
| | | |
| | | |
| | | |
| +------+ |
| |
| |
| |
| |
+----------------------------------+
Fig. 13.-ELEVATION OF DOUBLE RECTANGULAR NOTCHED GAUGING WEIR.
+------+ +------+
| \ FIG. 13 / |
| \ / |
| \ / |
| \ / |
| \ / |
| \ / |
| \ / |
| \ / |
| \ / |
| \/ |
| |
| |
| |
| |
| |
+----------------------------------+
FIG.
Pages:
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73